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Niels Lohmann
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For idx == SIZE_MAX, the non-const array operator[] computed the new size as idx + 1, which wraps to 0. resize(0) then emptied the array, and the subsequent operator[](idx) on the now-empty vector wrote one element before its buffer. Every other too-large index (e.g. SIZE_MAX - 1) already went through resize(), which throws std::length_error and leaves the array unchanged; SIZE_MAX was the one value for which the overflow bypassed that safety net. Add a guard that throws std::length_error before computing idx + 1 when idx is the largest representable size_type value, so the array is left unchanged, matching the exception vector::resize() already throws for smaller (but still too large) indices. Fixes #5647. Signed-off-by: Niels Lohmann <mail@nlohmann.me>
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