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Currently hitting ^C prints out two stack traces, requiring scrolling up though multiple screens of scrollback to get back to the autoupdate results. This primarily shows up when hitting ^C while it's symbolizing a C++ stack trace.
90 lines
2.7 KiB
Python
Executable File
90 lines
2.7 KiB
Python
Executable File
#!/usr/bin/env python3
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"""Runs bazel on arguments.
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This is provided for other scripts to run bazel without requiring it be
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manually installed.
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"""
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__copyright__ = """
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Part of the Carbon Language project, under the Apache License v2.0 with LLVM
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Exceptions. See /LICENSE for license information.
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SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception
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"""
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import argparse
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import subprocess
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import sys
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import time
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import scripts_utils
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def main() -> None:
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parser = argparse.ArgumentParser(description="Runs bazel.")
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parser.add_argument(
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"--attempts",
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metavar="COUNT",
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type=int,
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default=1,
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help="The number of attempts to execute the command, automatically "
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"retrying errors that may be transient.",
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)
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parser.add_argument(
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"--jobs-on-last-attempt",
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metavar="COUNT",
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type=int,
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help="Sets the number of jobs in user.bazelrc on the last attempt. If "
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"there is only one attempt, this will be set immediately.",
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)
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parser.add_argument(
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"--retry-all-errors",
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action="store_true",
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help="Retries permanent errors in addition to transient.",
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)
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script_args, bazel_args = parser.parse_known_args()
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bazel = scripts_utils.locate_bazel()
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attempt = 0
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while True:
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attempt += 1
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if attempt == script_args.attempts and script_args.jobs_on_last_attempt:
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with open("user.bazelrc", "a") as bazelrc:
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bazelrc.write(
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f"build --jobs={script_args.jobs_on_last_attempt}\n"
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)
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p = subprocess.run([bazel] + bazel_args)
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# If this was the last attempt, or it succeeded, we're done.
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if attempt == script_args.attempts or p.returncode == 0:
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exit(p.returncode)
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# Several error codes are reliably permanent, break immediately.
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# `1` -- The build failed.
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# `2` -- Command line or environment problem.
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# `3` -- Tests failed or timed out, we don't retry at this layer
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# on execution timeout.
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# `4` -- Test command but no tests found.
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# `8` -- Explicitly interrupted build.
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#
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# Note that `36` is documented as "likely permanent", but we retry
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# it as most of our transient failures actually produce that error
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# code.
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perm_error = (1, 2, 3, 4, 8)
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if not script_args.retry_all_errors and p.returncode in perm_error:
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exit(p.returncode)
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print(
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f"Retrying exit code {p.returncode} because it may be transient..."
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)
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# Also sleep a bit to try to skip over transient machine load.
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time.sleep(attempt)
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if __name__ == "__main__":
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try:
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main()
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except KeyboardInterrupt:
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sys.exit(1)
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